t=-16t^2+15t+10

Solution for t=-16t^2+15t+10 equation:

t=-16t^2+15t+10

We move all terms to the left:

t-(-16t^2+15t+10)=0

We get rid of parentheses

16t^2-15t+t-10=0

We add all the numbers together, and all the variables

16t^2-14t-10=0

a = 16; b = -14; c = -10;
Δ = b2-4ac
Δ = -142-4·16·(-10)
Δ = 836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{836}=\sqrt{4*209}=\sqrt{4}*\sqrt{209}=2\sqrt{209}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{209}}{2*16}=\frac{14-2\sqrt{209}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{209}}{2*16}=\frac{14+2\sqrt{209}}{32}
$